#include<stdio.h>

int main()
{
	int sum;//邮票总数
	int a,b,c=303;
	//sum=10605/(28-5*x) x的取值为1到5
	for(int x=1;x<=5;x++)
	{
		if((10605%(28-5*x))==0)
		{
			sum=10605/(28-5*x);
			a=sum/5;
			b=sum-a-c;
			break;
		}
	}
	printf("sum:%d\n a:%d\n b:%d\n c:%d\n",sum,a,b,c);

	
	return 0;
}







